GMAT Speed, Time & Distance: A Guide to Relational Motion & DS Strategy

Speed, Time, and Distance (TSD) questions are a cornerstone of GMAT Quantitative Reasoning and Data Insights. Beyond basic calculation (Distance = Speed × Time), the GMAT tests your mastery of algebraic rate expressions, average speed weighted logic, relative motion (catch-up and collision scenarios), and Data Sufficiency rephrasing.

Section 1: The Core TSD Framework & Proportionality

The TSD Triangle & Unit Conversions

Master the fundamental Distance = Speed × Time relationship, explore the 3 algebraic rearrangements, and practice instant unit conversions with our interactive tool.

The TSD Triangle & Unit Conversions

The Fundamental Motion Formula

All motion questions test the relationship between three variables: Distance, Speed (Rate), and Time.

Distance
$$ D = S \times T $$

Distance = Speed × Time

Speed
$$ S = \frac{D}{T} $$

Speed = Distance / Time

Time
$$ T = \frac{D}{S} $$

Time = Distance / Speed

Golden Rule of Units: Units across all 3 variables must always be compatible. If speed is in miles per hour (mph), time must be in hours and distance in miles. If speed is in meters/sec, time must be in seconds.
1Tab 1 of 3The Core Formulas

Speed-Time Proportionality & Multipliers

Master inverse variation (constant distance) and direct variation (constant time) with step-by-step interactive problem models.

Speed, Time & Proportionality

Constant Distance: Inverse Speed-Time Ratio

When distance is constant, Speed and Time are inversely proportional.

If speed is multiplied by k, time required becomes 1/k.

Step 1The Problem

Carl and Ruth

Carl averaged 2m mph on a trip that took him h hours.
If Ruth made the same trip in (2/3)h hours, what was her average speed in mph?

Step 2Method 1: The Algebraic Approach (Formula)

Step A: Find the total distance.

$$ \text{Distance } (D) = \text{Speed} \times \text{Time} = (2m) \times h = 2mh $$

Step B: Divide distance by Ruth's time.

$$ \text{Ruth's Speed} = \frac{D}{\text{Ruth's Time}} = \frac{2mh}{\frac{2}{3}h} = 2mh \times \frac{3}{2h} = \mathbf{3m \text{ mph}} $$

Notice that variable h cancels out cleanly.

Step 3Method 2: The Ratio Shortcut (Proportionality)

Principle: For constant distance, the speed ratio is the inverse of the time ratio:

$$ \frac{S_1}{S_2} = \frac{T_2}{T_1} $$

Step A: Compare their times.

Ruth's time is 2/3 of Carl's time (ratio of Carl's time to Ruth's time is 3 : 2).

Step B: Invert the ratio for speed.

Since speed is inversely proportional to time, Ruth's speed must be 3/2 of Carl's speed:

$$ \text{Ruth's Speed} = \frac{3}{2} \times (2m) = \mathbf{3m \text{ mph}} $$

Step 4Key Takeaway

Why use the Ratio Shortcut?

The algebraic method requires setting up and simplifying compound algebraic fractions. The ratio shortcut lets you solve it in 5 seconds mentally: Time scaled by 2/3 → Speed scaled by 3/2 → (3/2) × 2m = 3m.

1Tab 1 of 2Constant Distance (Inverse Ratio)

The Average Speed Trap

Learn the crucial difference between simple average of speeds and the correct "Total Distance / Total Time" formula for complex journeys.

The Average Speed Trap

Car travels A to B at 40 km/hr.
Returns B to A at 60 km/hr.

What is the average speed?

1Tab 1 of 3The Problem

Section 2: Relative Motion & Advanced Problem Types

Relative Speed Concepts

Master the two core scenarios for relative speed (objects moving in opposite vs. same directions) using a visual race simulator.

Opposite Direction (Add Speeds)

A (2 m/s) and B (3 m/s) are 100m apart.

🏃‍♂️ A
🏃‍➡️ B
1Tab 1 of 2Opposite Direction

Advanced TSD Scenarios: Trains, Boats & Escalators

Apply relative speed concepts to the classic GMAT problem types involving trains crossing platforms, boats in streams, and escalators.

Step 1Scenario

100m train crosses 300m platform at 20 m/s.

Step 2Total Distance

Distance = Train Length + Platform Length
$$ D = 100 + 300 = 400 \text{ m} $$

Step 3Time

$$ T = \frac{400}{20} = 20 \text{ seconds} $$
1Tab 1 of 3Trains

Section 3: GMAT Strategy & Data Sufficiency

GMAT Strategy: Data Sufficiency in Motion Problems

Apply interactive Data Sufficiency strategies to TSD. Learn how to rephrase question stems, evaluate weighted sums directly, and compare meeting point proximity.

GMAT Data Sufficiency: Speed, Time & Distance

DS: Target Expression Evaluation

Look for the combined algebraic expression (2x + 3y) rather than solving for individual variables x and y.

Step 1The Problem

Marta's Average Speed

Marta averaged x mph for 2 hours and y mph for the remaining 3 hours. What was her average speed, in miles per hour, for the entire trip?

(1) 2x + 3y = 280

(2) y = x + 10

Step 2Step 1: Rephrase the Question Stem

Total Distance = 2x + 3y

Total Time = 2 + 3 = 5 hours

$$ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{2x + 3y}{5} $$

Strategic Rephrase: We only need the exact value of the expression (2x + 3y) to find the answer.

Step 3Step 2: Analyze Statement (1)

$$ 2x + 3y = 280 $$

Substitute 280 directly into our target expression:

$$ \text{Average Speed} = \frac{280}{5} = \mathbf{56 \text{ mph}} $$

A unique numerical value is obtained → SUFFICIENT.

Step 4Step 3: Analyze Statement (2)

$$ y = x + 10 $$

Substitute y into our target expression:

$$ \text{Average Speed} = \frac{2x + 3(x + 10)}{5} = \frac{5x + 30}{5} = x + 6 $$

Since x is unknown, the average speed can vary → INSUFFICIENT.

Final Answer: (A)

1Tab 1 of 2Example 1: Weighted Average Speed
Topic Drill in Preparation

Topic Drill Coming Soon

A dedicated question set for Speed, Time & Distance is currently being authored. In the meantime, test your baseline score on the full Diagnostic: